In the figure, if O is the centre of the circle then find angle AOB?
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Angle AOB = 120° { 2:1 theorem } only if angle OAC = angle OBC = 30°
But, if angle OAC is 20° and angle OBC is 30°, then angle AOB = 100° { 2:1 theorem.
But, if angle OAC is 20° and angle OBC is 30°, then angle AOB = 100° { 2:1 theorem.
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HELLO FRIEND...
HERE IS YOUR ANSWER...
OA = OC (Radii of same circle)
=> Angle OAC = Angle OCA
=> Angle OCA = 20°
Similarly, Angle OCB = 30°
Angle ACB = 50°
Therefore, Angle AOB = 100°.
# GUDIYA...
HOPE IT HELPS !! ☺☺☺
HERE IS YOUR ANSWER...
OA = OC (Radii of same circle)
=> Angle OAC = Angle OCA
=> Angle OCA = 20°
Similarly, Angle OCB = 30°
Angle ACB = 50°
Therefore, Angle AOB = 100°.
# GUDIYA...
HOPE IT HELPS !! ☺☺☺
GAUTHAM46:
thanks a lot
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