Question

in the figure if our area triangle Ras equals to area triangle RBS and a triangle cube equals to a triangle p a s then show the both equilateral P Q R and r s b a r trapezium

Answer 1

Answer:

In given figure area(ΔRAS)=area(ΔRBS) and area(ΔQRB)=area(ΔPAS)

Given area(ΔRAS)=area(ΔRBS)

(1)

This possible when those triangles in (1) are equal on same base RS and two line AB and RS

Then line RS and AB are parallel each other

So RSAB is a trapezium

Given area(ΔQRB)=area(ΔPAS)

Less area(ΔRAS) and area(ΔRBS) we get

⇒area(ΔQRB)−area(ΔRAS)=area(ΔPAS)−area(ΔRBS)

⇒area(ΔQRS)=area(ΔPSR) (2)

This possible when those triangle are in (2) On same base RS and two line PQ and RS

Then line RS and PQ are parallel each other

So RSAB is a trapezium

So PQRS and ABRS are trapezium