Question

In the figure, if quadrilateral PQRS circumscribes a circle, then PB + SD =​

Answer 1

Answer:

PS

Step-by-step explanation:

PB=PA(TANGENTS HERE IS EQUAL)

and

SD=SA (TANGENTS HERE IS EQUAL)

adding both we get PS

Answer 2

Answer:

In the figure, if quadrilateral PQRS circumscribes a circle, then PB + SD=PS

Step-by-step explanation:

The tangents drawn to a circle from the same external point will be equal in length.

Therefore,

PA=PB      ..(1)

SA=SD      ..(2)

On adding the equations one and two we get,

PA+SA=PB+SD

Therefore, PB+SD=PS

Thus, In the figure, if quadrilateral PQRS circumscribes a circle, then PB + SD=PS​.