Question

In the figure if the line pq and RS intersect at point T such that anglePRT=40⁰, angle RPT=95⁰, angle TSQ=75 find angleSQT

Answer 1

Answer:  

Solution:

In ∆PRT, we have

∠PRT+∠RPT+∠RTP=180°   (Sum of three angles of a triangle =180°)

⇒40°+95°+∠RTP=180°

⇒∠RTP=180°−40°−95°=45°

∠RTP=∠QTS     (Vertically Opposite Angles)

Therefore, ∠QTS is also equal to 45°

In ∆STQ, we have

∠SQT+∠TSQ+∠QTS=180°  (Sum of three angles of a triangle =180°)

⇒∠SQT+75°+45°=180°

⇒∠SQT=180°−75°−45°=60°

I hope, this will help you.☺