In the figure if Traingle POQ is similar to.SOR PQ:RS=1:2 than OP:OSis
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To prove:- △POQ∼△SOR
Proof:-
In △POQ and △SOR
∠POQ=∠SOR[∵Vertically opposite angles]
∠P=∠S[∵As PQ∥RS, Alternate angles]
∠Q=∠R[∵As PQ∥RS, Alternate angles]
Using AAA similarity function criteria,
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