Question

In the figure, if ZACB = ZCDA. AC = 6 cm and AD = 3 cm, then find the length of AB​

Answer 1

Answer:

according to question

in ∆ACB and ∆ ACD

angle ACB = angle CDA

AC = AC

so

∆ ABC is similar to ∆ ACD

AB/AC = AC/AD

AB / 6 = 6/3

AB = 6 x 2

AB = 12cm

Answer 2

Answer:

triangle ACB~ADC

as angle a common &c= given

AC/AD=AB/AC

sqAC=AB*AC

AB=6*6/3

AB=2*6

AB=12

Step-by-step explanation: