In the figure, if ZACB = ZCDA. AC = 6 cm and AD = 3 cm, then find the length of AB
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Answered by
21
Answer:
according to question
in ∆ACB and ∆ ACD
angle ACB = angle CDA
AC = AC
so
∆ ABC is similar to ∆ ACD
AB/AC = AC/AD
AB / 6 = 6/3
AB = 6 x 2
AB = 12cm
Answered by
26
Answer:
triangle ACB~ADC
as angle a common &c= given
AC/AD=AB/AC
sqAC=AB*AC
AB=6*6/3
AB=2*6
AB=12
Step-by-step explanation:
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