Question

in the figure in ∆ABC,BC= 16 cm, AC= 12cm,AB= 10 cm and altitude AD= 6 cm.Find BE and altitude on side AB​

Answer 1

The value of BE is 8 cm and altitude on side AB is 9.6 cm.

Step-by-step explanation:

Since we have given that

In ∆ABC,

BC = 16 cm

AC = 12 cm

AB = 10 cm

altitude = AD = 6 cm

Area of triangle with height AD and base BC,

$\dfrac{1}{2}\times AD\times BC\\\\=\dfrac{1}{2}\times 6\times 16\\\\=8\times 6\\\\=48\ cm^2$

Now, area with base AC and height BE,

$48=\dfrac{1}{2}\times BE\times AC\\\\48=\dfrac{1}{2}\times BE\times 12\\\\48=BE\times 6\\\\\dfrac{48}{6}=BE\\\\BE=8\ cm$

Area of triangle with altitude on side AB is given by

$48=\dfrac{1}{2}\times AB\times h\\\\48=\dfrac{1}{2}\times 10\times h\\\\48=5\times h\\\\h=\dfrac{48}{5}\\\\h=9.6\ cm$

Hence, the value of BE is 8 cm and altitude on side AB is 9.6 cm.

# learn more:

In the figure, in triangle ABC, BC=16cm, AC=12cm, AB=10cm and altitude AD=6cm.Find (a)BE (b)altitude on side AB.​

Answer 2

Answer:

ans is 15cm and13cm

2+55 221--89 m 99*66 cm0796