in the figure, is ∆DAC congruent to ∆BCA? if so, are the following true? give reasons. (a) AD=BC. (b) DC=AB. (c) ABCD is a parallelogram.
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How can I prove 2(AB^2- BC^)=BC^2 if BD:DC=3:1 in a ∆ABC where AD is perpendicular to BC?
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