in the figure, is ∆DAC congruent to ∆BCA? if so, are the following true? give reasons. (a) AD=BC. (b) DC=AB. (c) ABCD is a parallelogram.
Attachments:
![](https://hi-static.z-dn.net/files/da0/56ba3c09d10d3042d2a709980fda7687.jpg)
Answers
Answered by
0
Answer:
How can I prove 2(AB^2- BC^)=BC^2 if BD:DC=3:1 in a ∆ABC where AD is perpendicular to BC?
Answered by
2
hope it helps
have a great day
Attachments:
![](https://hi-static.z-dn.net/files/df9/0c2f8f13ed33595f8fc995ce8666cd16.jpg)
Similar questions