In the figure is the centre of circle. is angle A = 32, Find all angles of triangle A B C 2320
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Use pythagoras theorem to solve this
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AB is a diameter and so angle ABC is an angle in a semi- circle
Therefore angle ACB =90°
AO =OC(radius of a circle)
AO=OC=OA=60°
In triangle AOC
angle A + angle C + angle A =180°
60+60+60=180°
180°=180°
Therefore, Angle CAB =60°
again, angle CAB + angle ABC+angle BCA= 180°
60° + angle ABC +90°=180°
Angle ABC=180°-150°
Therefore, angle ABC=30°
Thus, angle ACB=90°, angle CAB=60° and angle ABC=30°
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