Question

In the figure, it is given that Ilm and t is a transversal such that 2 1 = 135. Find 22, 23, 24, 25, 26, 27 and
equal to 3 cm, cut PE at C.
(v) With Q as centre and radius equal to 3 cm , cut QF at D.
(vi) Join CD and produce it on either side to get the required the parallel to AB and at a
distance of 3 cm from it.
Exercise - 35
8.
1
135°
12
>1
4)
3
5
8
7
In the given figure, ABCD is a quadrilateral in which ZA= ZB = ZC= _D = 90°. Prove that AD || BC and
Give reasons in support of your answer.​

Answer 1

Answer:

Sum of the angles of a triangle is 180°.

Sum of any two sides of a triangle is greater than the third side.

Area of a rectangle = length * breadth.

Area of a square = side^2 = 1/2(diagonal)^2

Area of a circle = π * r*r ; r = radius and π / PI = 22/7 or 3.14

Area of a kite: 1/2 * (sum of the length of two diagonals)

Area of a semi circle = π * r * r / 2 ; Circumference = π * r

To find the area of a parallelogram, just multiply the base length (b) times the height (h): Area = b * h