Question

in the figure KLMN is a trapezium and its area 90cm² Area of truangle is 70cm². what is the pecularity of the sides KL and NM? what is the area of triangle KNL? what is the area of triangle LMN?​

Answer 1

Answer:

answer will be 600 cm 2

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Answer 2

Step-by-step explanation:

In Δs KLN and KLM KN = LM (Isos. trap.) ∠NKL = ∠KLM (Prop. of isos. trap.) KL = KL (Common) ∴ ΔKLN ≅ ΔKLM (SAS) ⇒ ∠KML = ∠KNL =25° (c.p.c.t.) ∴ ∠LMN = 25° + 30° = 55° Now ∠KNM =∠LMN ⇒ ∠KNL + ∠LNM = 55° ⇒ ∠LNM = 55° – 25° = 35° In ΔNXM, ∠NXM = 180° – (∠XNM + ∠XMN) = 180° – (30° + 30°) = 180° – 60° = 120° (i) Now, ∠KXN = 180°– ∠NXM = 180° – 120° = 60° (Linear pair) Also, ∠LXM = ∠KXN = 60° (ii) Now, in ΔMLX, ∠MLX (∠MLN) = 180° – (60° + 25°) = 180° – 85° = 95°