In the figure, L is parallel to M and T is a transversal. If angle 1 and angle 2 are in the ratio of 5:7, find the measure of the following angles : 1,2,3 and 8
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Two parallel lines l and m be cut a transversal t, forming angles.
It is given that ∠1:∠2=5:7
Let the measures of angles by 5x and 7x,
Then,
5x+7x=180
12x=180
x=180/12
x=15
∴∠1=5x=5×15=75 degree
∠2=7x=7×15=150 degree
We know that,
∠2+∠3=180 degree
......[∵ linear pair]
105 degree +∠3=180 degree
=∠3=180−105
∠3=75 degree
∠3+∠6=180 degree
......[∵ the sum of the consecutive interior angles is 180 degree
75 degree +∠5=180 degree
∠6=180−75
∠6=150 degree
Now ∠6=∠8=150 degree
.....[∵ vertically opposite angles are equal]
∴∠1=75 degree,
∠2=105 degree,
∠=75 degree
and ∠8=105 degree.
Hope it helps please mark my answer as brainliest.
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