Question

in the figure line AB || line CD and line PQ is transversal . Ray PT and ray QT are bisectos of angle BPQ and angle PQD respectively . Find measure of angle PTQ.
​

Answer 1

<BPQ + <DQP = 180 (Interior angles)

<BPQ/2 + <DQP/2 = 180/2

<TPQ + <TQP = 90. ........1

In triangle PTQ,

<TPQ + <TQP + <PTQ = 180

(angle sum property)

<PTQ = 180 - 90 (from 1)

<PTQ = 90°

Answer 2

Answer:

Step-by-step explanation: