In the figure, line PQ | line RS and line AB is the
transversal. Which type of (ACBD is formed by
the bisectors of the interior angles ?
(1) Trapezium (2) Rhombus
(3) Rectangle (4) Square
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l||m and p intersects them at points A and C respectively. Bisectors of interior angles intersect at B and D.
Now PAC = ACR (alternate angles)
AB||DC (as alternate angles are equal)
Similarly BC||AD
ABCD is a parallelogram
Also PAC + CAS = 180o (Linear pair)
ABCD is a ||gm with one angle 90o
ABCD is a rectangle.
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