in the figure,line PQ ll side BC, AP = 2.4 CM,PB = 7.2 CM,=5.4cm; then find AQ
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Answer:
∵PQ∥BC
⇒∠APQ=∠ABC
and∠AQP=∠ACB(corespondinganglearesame)
∴△APQ∼△ABC(AAcriteria)
hence,
AB
Ap
=
AC
AA
⇒
AP
AB
=
AQ
AA
⇒
AP
AB
−1=
AQ
AC
−1
⇒
AP
PP
=
AQ
QC
⇒
2.4
7.2
=
AQ
5.4
⇒AQ=1.8cm
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