Question

in the figure LM||AB.AL=x-3,AC=2x,BM=x-2and BC=2x+3 find the value of x

Answer 1

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Answer 2

Here LM ║ AB .

AC = AL+ LC                     BC = BM + MC

LC = 2x-(x-3) = x+3           MC = 2x+3-(x-2) = x+5

AL/LC      =   BM/MC

(x-3)/(x+3)  =  (x-2)/(x+5)

(x-3)(x+5)   =  (x-2)(x+3)

 x²+2x-15    =  x²+x-6

 2x-x            =  15-6

  x  =  9