Math, asked by vellankivignesh, 1 year ago



In the figure LM//CB and
LN //CD then show that
AM AN
MB ND

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Answers

Answered by Anonymous
20

In the given figure, we can see, LM || CB,

By using basic proportionality theorem, we get,

AM/MB = AL/LC …..(i)

Similarly, given, LN || CD and using basic proportionality theorem,

AN/AD = AL/LC ……(ii)

From equation (i) and (ii), we get,

AM/MB = AN/AD

Hence, proved.

Answered by Anonymous
25

In the given figure, we can see, LM || CB,

By using basic proportionality theorem, we get,

AM/MB = AL/LC……………………..(i)

Similarly, given, LN || CD and using basic proportionality theorem,

∴AN/AD = AL/LC……………………………(ii)

From equation (i) and (ii), we get,

AM/MB = AN/AD

Hence, proved.

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