Question

In the figure LM//CB and LN//CD then show that AM/MB=AN/ND​

Answer 1

Answer:

In triangle(ABC):

AM/BM=AL/AC

And in triangle(ACD):

AL/AC=AN/ND

So AM/BM=AN/ND

Answer 2

In the given figure, we can see, LM || CB,

By using basic proportionality theorem, we get,

AM/MB = AL/LC …..(i)

Similarly, given, LN || CD and using basic proportionality theorem,

∴ AN/AD = AL/LC ……(ii)

From equation (i) and (ii), we get,

AM/MB = AN/AD

Hence, proved.