Question

in the figure <A=60°
CE||BA & <ECD=65° find <ACB​

please help meee

Answer 1

Answer:

angle ACB = 55°

Step-by-step explanation:

AB || CE

AC is the transversal

therefore angle BAC = angle ACE = 60°

BCD is a straight line

the angle is 180°

we can say

angle ACB + angle ACE + angle ECD = 180°

angle ACB + 60° + 65° = 180°

angle ACB + 125° = 180°

angle ACB = 180° - 125°

angle ACB = 55°

hope you get your answer

Answer 2

Answer:- Angle ABC :-55 degree