Question

In the figure <A = <C = 90', <ADB = 450, <DBC = 30,BD =
8om.al.com
90°
a) What is the length of AB ?
b) What is the perimeter of ABCD?
c) What is the area of ABCD ?
304
А​

Answer 1

Answer:

Step-by-step explanation:

If BD = 8 units and m∠CBD = 30° , then CD = 4 units

CB = √(8² - 4²) = √48 = 4√3 units

(a). AB = AD, 2AB² = 8² , AB = 4√2 units

(b). $P_{ABCD}$ = 2 × 4√2 + 4 + 4√3 = (4√3 + 8√2 + 4) units

(c). $A_{ABCD}$ = $A_{ABD}$ + $A_{BCD}$ = 16 + ( 4√3 × 4 ) = 16(1 + √3) units²