Question

In the figure ,<ABC=<BCD=90° and AC=BD.Prove that:Triangle ABCis congurent to Triangle BCD.

Answer 1

in ∆ABC and ∆ DCB

BC = BC (common base)
/_ ABC = /_ BCD = 90°
AC = BD (given)

therefore , using RHS congruence criteria


∆ABC is congruent to ∆DCB


hope this helps

Answer 2

See attachment, I hope you got it .