In the figure, <B is the right angle of ABC. write the following ratios: i) sinc ii) Cos C ii) tan c iv) Sin A
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here,
perpendicular (P)=AB
base(B)= BC
Hypotenuse (H)= AC
sinC= P/H= AB/AC
cosC= B/H = BC/AC
tanC= P/B = AB/BC
For sinA,
perpendicular (P)= BC
hypotenuse (H)= AC
therefore, sinA= P/H = BC/AC
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