In the figure < BAD =3 <DBA , find <DBC and <ABC
Answers
Answered by
0
Answer:
consider triangle BAD
sum of 3 angles =180
angle D = 104
and angle A =3xangle B
Therefore 180-104=76 and 76/4=19
divide by 4 since 3 part of angle B and one part of angle A
therefore angle BAC =57 °
now angle DBC =180-(65+57)-19=39
and Angle CFB =180-104 =76 °
Step-by-step explanation:
pls mark me as brainliest.
Similar questions