In the figure, m(arc APC) = 100° and
angle BAC =70°.
Find :-
a) angle ABC
b) m(arcBQC)
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Answer:
Given :- In the figure, m (arc APC) = 100° and ∠BAC = 70°.
Find :-
i. ∠ABC
ii. m (arc BQC).
Solution :-
→ ∠ABC = (1/2) * (m arc APC) { inscribed angle theorem. }
→ ∠ABC = (1/2) * 100°
→ ∠ABC = 50° (Ans.)
similarly,
→ ∠BAC = (1/2) * m (arc BQC)
→ 70° = (1/2) * m (arc BQC)
→ 2 * 70° = m (arc BQC)
→ m (arc BQC) = 140° (Ans.)
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