In the figure, m (arc APC) = 100° and ∠BAC = 70°. Find i. ∠ABC ii. m (arc BQC).
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Given :- In the figure, m (arc APC) = 100° and ∠BAC = 70°.
Find :-
- i. ∠ABC
- ii. m (arc BQC).
Solution :-
→ ∠ABC = (1/2) * (m arc APC) { inscribed angle theorem. }
→ ∠ABC = (1/2) * 100°
→ ∠ABC = 50° (Ans.)
similarly,
→ ∠BAC = (1/2) * m (arc BQC)
→ 70° = (1/2) * m (arc BQC)
→ 2 * 70° = m (arc BQC)
→ m (arc BQC) = 140° (Ans.)
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