Question

In the figure mass M = 10 gm. is placed on an
inclined plane. In order to keep it at rest, the
value of mass ‘m' will be- ​

Answer 1

Answer:

the answer is the mass of smaller body is 5gm

Answer 2

Answer:

The value of the mass “m” = 5 gm  

Explanation:

The mass of the body on the inclined plane is “M” which is equivalent to 10 gm. The inclined plane is at an angle of 30 degrees. The small mass or “m” is pulling the mass of “M” downward similarly the mass “M” is also pulling the weight of the mass “m”.

The yellow line tell us the downward force of “M” as Mg.$\sin \theta$, the blue line tells the horizontal motion of the mass “m” as Mg.$\cos \theta$ whereas the green line tell us about the downward force of the small mass “m” as we can see that the vertical motions of Mg$\sin \theta$ and m are in same direction therefore the value of mass m with respect to mass M and keeping both the masses in equilibrium is  

$M g \sin \theta=m g$

$m=M \sin \theta$

Putting the values in M and θ we get the value of “m” as

$m=10 . \sin 30^{\circ}$

Therefore, the value of “m” = 5gm.

In according to the diagram, drawn below the attached file: