Question

in the figure ML parallel BC and NL Paralle DC ,prove that AM\AB=AN/AD.

Answer 1

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STEP BY STEP EXPLAINATION ÷

In triangle ABC. ML|| CB

=AM/BM =AL/ CL eq-1) by BPT

THEOREM

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NOW. , In triangle ADC LN || D C

=AN/DN. = AL/CL. Eq -2) by BPT

THEOREM
===================================
From comparing eq 1 and eq 2 we get

》AM/BM = AN/DN
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ ~~~~~~~~

{NOW WE ADD 1 ON BOTH SIDE }

》》 AM/BM +1 = AN/DN + 1

~》 AM / BM +AM. = AN / BM +AM

》》 AM / AB. = AN / AD

HENCE PROVED

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Answer 2

Step-by-step explanation:

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