Question

In the figure, ∠MNP = 90°, seg NQ ⊥ seg MP, MQ = 16, QP = 4, find NQ
a)Solution: In △MNP ∠MNP = 90°, seg NQ ⊥ seg MP, ∴ NQ² = _____________.......(by theorem of geometric mean)
b)Refering the above solution, ∴ NQ = _____​

Answer 1

Answer:Given;

In triangle MNP, angle MNP=90.

Seg NQ ⊥ Side MP.

MQ=9, QP=4.

To find;

l (seg NQ)

Solution;

Given that in right angled triangle MNP, seg (NQ) ⊥ seg (MP).

Hence we can use property of geometric mean.

Using property of geometric mean in Triangle MNP,

                 NQ² = MQ × QP

MQ=9, QP=4 is given.

NQ²= 9×4.

NQ²= 36.

Taking square roots on both sides,

NQ=6.

Answer;

The length of seg NQ= 6.

Answer 2

Answer:

hope it help you Dear......