In the figure nearby, chord AC and chord DE
intersect each other in point B.
i. If m(arc AE) = 50, m( arc DC) = 140,
then < DBC = ? < ABD = ?
ii. If m(arc AD) =70, m< EBC = 50, then
m(arc EC)= ?
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Step-by-step explanation:
In a circle angle subtended by any chord on opposite sides are supplementary.
So m(arcAPC)+m(arcABC)=180o
So m(arcABC)=180o−60o=120o
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