Question

In the figure (not drawn to scale) given below,P is a point on AB such that AP:PB = 4:3 .PQ is parallel to AC and QD is parallel to CP. In triangle ARC, angle ARC = 90 and in triangle PSQ = 90. The length of Qs is 6cm. If the ratio AP:PD = k then 3k =​

Answer 1

Answer:

7:3 IND.

Step-by-step explanation:

Given,AP/PB =4/3

AP/PB = QC/QB = 4/3

BD/PD = QB/QC =3/ 4

PB = BD + PD = 3+4 = 7

PB/PD = 7/4

AP/PB * PB/PD = 4/3 * 7/4

AP/PD =7/3

thus AP : PD = 7 : 3

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