Question

In the figure O ABCD is square triangles drawn
on side Bc and hypotenuse Ac arc DBCEN AACE
then prove that A CABCE) = 1 A COACF)
r
D
B​

Answer 1

Answer:

Step-by-step explanation:

△ABC and △DCB both are right angled triangle.

⇒ Both triangle have common hypotenuse.

⇒ In △ABC and △DCB

⇒ AC=DB [Given]

⇒ BC=CB [Common side]

∴ △ABC≅△DCB [By RHS property]