Question

In the figure, o is centre of circle such that diameter AB=13cm and AC=12cm. BC is joined. Find the area of shaded region.

Answer 1

Heya!!

Now,AB=13 cm
AC=12 cm

Since ABC is a right triangle,
[AC + BC]square = AB square
144 + BC square = 169
BC square = 25
BC = 5 cm

Since AB is the diameter,
Area of Shaded region = Area of 1/2 triangle - Area of triangle ABC

Area of 1/2 circle = 1/2 * 3.14 * 6.5 * 6.5
= 66.3 cm sq.

Area of triangle = 1/2 * 5 * 12
= 30 cm sq.

Therefore.
Area of Shaded region = 66.3 - 30
= 36.3 cm sq.


HOPE IT HELPS :)

Answer 2

Here your answer
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AB is 13cm and AC is 12cm
since ABC is a right triangle......
By Pythagoras theorem
BC is 5cm
Ar. of shaded region =Ar. of 1/2 triangle - Ar. of triangle ABC
Ar. of 1/2 circle =1/2×3.14×13/2×13/2
=66.3cm²
Ar. of triangle =1/2×5×12
=30cm²
therefore Ar. of shaded region=66.3-30
=36.3cm²
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