Question

in the figure, O is in the centre<BOC=130°,<AOB=110°.ehat is the measure of<AOC.Find the angles of<ABC

Answer 1

angle O is 360 degree
let AOC =x
so
x+130+110=360
x+240=360
therefore
x=360-240
x=120

Answer 2

angle AOC = 360° - (130° + 110°)
angle AOC = 120 °
then ,
angle A = half of angle BOC ( by theorem - the angle substended by an arc from the centre is double the angle substended by it at any point ...)
angle A = 130° ÷ 2
angle A = 65 °
similarly ,
angle B = half of angle AOC
angle B = 120 °÷ 2
angle B = 60 °
and
angle C = half of angle AOB
angle C = 110°÷2
angle C = 55 °
hope this will help uhh .....
if then mark as brainliest ..