In the figure, o is the center of a circle passing through points a,b,c and d and angle ADC = 120°. Find the value of x
solve this question without using ( angle in semi circle ) on ACB
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Answer:
ABCD is a cyclic quadrilateral. we have
∠ABC+∠ADC=180
∠ABC=180 −120 =60
Also ∠ACB=90 ( angle on a semi circle )
In ΔABC we have
∠BAC+∠ACB+∠ABC=180
∠BAC+90 +60 =180
∠BAC=180 −150
=30
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