in the figure, o is the center of the circle. aoc=70⁰, find bco
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angle boc = 180-70 =110°(straight line angle)
in triangle obc
angle c = angle b=x ( angles formed from radius of the same circle)
110+x+x=180°(sum of angles in a triangle)
2x=180-110
x=35°
Therefore angle bco = 35°
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