In the figure O is the center of the circle, ∠DOB= 120degree. Find the value of x.\
How did we get the answer? Please explain
Answers
Answer:
30°
Step-by-step explanation:
The angle of angle BOD = 120°
Then angle AOB = angle AOD-BOD = 180°-120° = 60°
AD and BC are parallel lines so let the point of intersection as M
so the value of angle M= 90°
It is 90°so 180° - 90° is 90° on the other side also
Now angle B = 180°-(angle m+ angle BOA)
180°-(90°+60°)
180°-150°
30°
Now the value of angle AMC = 90°
angle A is equal to angle BOC = 60°
So at last x° = 180° - (90°+60°)
180° - 150°
30°
Answer:
angle BOD = 120°
angle AOB = angle AOD - BOD = 180°- 120° = 60°
AD and BC are parallel lines, let the intersecting point be M
angle M = 90°
since angle m is 90°,
180°- 90° = 90°
Now angle B = 180°- (angle m + angle AOB)
180° - (90° + 60°)
180° - 150° = 30°
angle AMC = 90°
angle A = angle BOC = 60°
x = 180° - (90°+60°)
180° - 150° = 30°
thus x = 30°
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