Question

In the figure O is the center of the circle, ∠DOB= 120degree. Find the value of x.\
How did we get the answer? Please explain

Answer 1

Answer:

30°

Step-by-step explanation:

The angle of angle BOD = 120°

Then angle AOB = angle AOD-BOD = 180°-120° = 60°

AD and BC are parallel lines so let the point of intersection as M

so the value of angle M= 90°

It is 90°so 180° - 90° is 90° on the other side also

Now angle B = 180°-(angle m+ angle BOA)

180°-(90°+60°)

180°-150°

30°

Now the value of angle AMC = 90°

angle A is equal to angle BOC = 60°

So at last x° = 180° - (90°+60°)

180° - 150°

30°

Answer 2

Answer:

angle BOD = 120°

angle AOB = angle AOD - BOD = 180°- 120° = 60°

AD and BC are parallel lines, let the intersecting point be M

angle M = 90°

since angle m is 90°,

180°- 90° = 90°

Now angle B = 180°- (angle m + angle AOB)

180° - (90° + 60°)

180° - 150°  = 30°

angle AMC = 90°

angle A = angle BOC = 60°

x = 180° - (90°+60°)

180° - 150°  = 30°

thus x = 30°

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