In the figure, O is the center of the circle. If ∠BAC = 50°, find ∠BOC
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To theorem: angle subtended by an arc at the center of the circle is double to the handle subtended at the another part of the circle.
So,a angle BOC= 2 angleBAC
angle BOC=2×50°
angle BOC= 100°
So,a angle BOC= 2 angleBAC
angle BOC=2×50°
angle BOC= 100°
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