in the figure o is the centre. if qor is 100 degree find qpr and qsr
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Answer:
qpr = 50°
qsr = 130°
Explanation
qpr = 100/2 ( angle subtended at the centre is twice the angle subtended at the circumference)
qpr = 50
qsr = (360 - 100)/2 ( 360 - 100 because we need find the other angle)
= 260/2
= 130
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< QPR = 50 ( <QOR/2 OR INSCRIBED ANGLE IS HALF OF CENTRAL ANGLE)
<QSR = <QOR(REFLEX)/2 (INSCRIBED ANGLE IS HALF OF CENTRAL ANGLE)
=260/2
=130
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