In the figure O is the centre of a circle. Angle AOB=110 then angle ACB=
Answers
Answered by
0
Answer:
Step-by-step explanation:
Correct option is
A
55
o
, 55
o
Given,
angle at centre ∠AOB=110
o
angle at circumference ∠ACO
Now,
we know that the angle at the centre is twice the angle at the circumference subtended by the same arc.
Therefore,
∠AOB=2∠ACO
⟹110
o
=2∠ACO
⟹∠ACO=
2
110
o
=55
o
Now,
∠COA+∠AOB=180
o
⟹∠COA=180
o
−110
o
=70
o
In△AOC,
∠AOC+∠ACO+∠CAO=180
o
⟹70
o
+55
o
+∠CAO=180
o
⟹∠CAO=55
o
Similar questions