in the figure o is the centre of a circle chord ab is equal to 10 cm and diameter AC is equal to 26 CM the distance of the chord ab of a circle from the centre is
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Let O be the centre,
Draw OM perpendicular to AC
» By Pythagoras theorem
» OA² = AM² + OM²
» 13² = 5² + OM²
» OM = 12 cm
Therefore, chord is at distance of 12 cm from the centre.
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