Question

in the figure,o is the centre of a circle. if angle BAD= 30 degree and angle ABC=55 degree ,find 1st angle BAC and angle ABD​

Answer 1

Answer:

Step-by-step explanation:

In Triangle ABD :

∠DAB + ∠ADB + ∠ABD = 180

30 + 90 + ∠ABD = 180

120 + ∠ABD = 180

∠ABD = 180 - 120

∠ABD = 60

In Triangle ABC:

90 + 55 + ∠BAC = 180

145 + ∠BAC = 180

∠BAC = 180 - 145

∠BAC = 35

Answer 2

Answer:

Step-by-step explanation:

First let us find triangle ACB :

55 degree+90 degree+x degree=180 degree          [ angle sum property ]

=>145 degree+x degree = 180 degree

=> x degree= 180 degree-145 degree

=> x degree=35 degree

x degree = /_ABD        [ ALTERNATE INTERIOR ANGLES ]

HENCE,  SOLVED

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