Question

in the figure o is the centre of a circle line AB BC CD and DA touches the circle in point E,F,G and H are respectively show that in quadrilateral ABCD sum of opposite sides are equal​

Answer 1

Answer:

Step-by-step explanation:

Given : Line AB, BC, CD and DA touches the circle in point E, F G and H respectively  

To Find : Show that sum of opposites sides of Quadrilateral ABCD is equal

Solution:AB, BC, CD and DA touches the circle in point E, F G and H
AE = AH       Equal Tangents
BE = BF       Equal Tangents
CF = CG      Equal Tangents
DG = DH      Equal Tangents
AE  + BE  + CG + DG  = AH + BF + CF  + DH
=>  ( AE + BE) + (CG + DG) = (AH + DH) + (BF + CF)
=>  AB + CD = AD + BCQED

Hence Proved