Question

in the figure ,O is the centre of a circle passing through the points A,B,C and D and angle ADC =l to 120° . find the value of x

Answer 1

plz clear the question......which angle is x

Answer 2

Answer:

$\huge\bold\purple{REQUIRED \: ANSWER:-}$

Solution:

Since ABCD is a cyclic quadrilateral

∠ADC + ∠ABC = 180°

[∴ opp. ∠s of a cyclic quad. are supplementary]

120° + ∠ABC = 180°

∠ABC = 180° – 120° = 60°

Now, ∠ACB = 90° [angle in a semicircle]

In rt. ∠ed ∆CB, ∠ACB = 90°

∠CAB + ∠ABC = 90°

x + 60° = 90°

x = 90° -60°

x = 30°

$\huge\boxed{\fcolorbox{blue}{orange}{hope it helps}}$