Question

in the figure O is the centre of circle measure of Arc pqr is equal to 90 Rupees equal to 10 cm find the area of the shaded region wise equal to 3.14​

Answer 1

$BA = \sqrt{ \:576 + 100. } \:$

(Pythagorean theorem)

BA = 26 cm

$BO = r = \frac{26}{2} = 13 cm$

Area of shaded region = Area of

semicircle - Area of triangle

$= \: \frac{ \:πr^2}{2} + ( \frac{1}{2} bh)$

$(3.14 × \frac{ \:169 \: }{2} + ( \frac{1}{2} × 24 × 10)$

$265.33 + 120 {cm}^{2}$

$385.33 cm^2 \:$

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