Question

in the figure O is the centre of circle with radius 3'cm.angle AOB= 60 degree.what is the perimeter of triangle AOB?

Answer 1

Step-by-step explanation:

OA OB (radius of the circle)

ZOBA=ZOAB (Opposite angles of equal sides are equal)

In AOB

Property of triangle:-

= ZOAB + ZAOB + ZOBA= 180 (Angle sum

property of triangle)

= 220AB+60=180 (from eq 1)

= 24OAB =180-60

= ZOAB = 120/2

= ZOAB = 60 = ZOBA

Since ZOAB = ZAOB = ZOBA = 60

Half answer:-

Therefore AOB is an equilateral triangle

AB=BO=BA= 3 cm

Perimeter of AAOB = AB+BO+BA

Next step:

= 3+3+3

= 9 cm

Therefore the perimeter of AAOB is 9 cm

$\:$

Required answer is 09 cm

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