in the figure o is the centre of the circle a b c d e are points on it find angle ADB angle ACB and angle DBC
Attachments:
Answers
Answered by
2
Step-by-step explanation:
∠EPD=∠BPC ( Vertically opposite)
∠EDB=180°-120° =60°(Opposite angles in a cyclic quadrilateral are supplementary)
∠PED=180°-60°-100°( triangle sum pproperty)
=180°-160°
=20°
∠DBC =∠PED =20°(Angles on the same segment)
Similar questions