Question

in the figure o is the centre of the circle a b c d e are points on it find angle ADB angle ACB and angle DBC​

Answer 1

Step-by-step explanation:

∠EPD=∠BPC ( Vertically opposite)

∠EDB=180°-120° =60°(Opposite angles in a cyclic quadrilateral are supplementary)

∠PED=180°-60°-100°( triangle sum pproperty)

=180°-160°

=20°

∠DBC =∠PED =20°(Angles on the same segment)