In the figure 'o' is the centre of the circle and A and B are points on the circle
a) Find the measurement of angle A?
b) What is the radius of the circle?
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here is ur ans
Angle A =60°
Radius =5cm
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OA and OB are the radii of the circle.
Thus, let OA and OB be x.
∆AOB is an isoceles triangle as OA and OB are equal.
Since, Isoceles triangles have two pairs of angles equal made by the equal sides.
Let Angles OAB and OBA be y.
Angle OAB + Angle OBA + Angle AOB = 180°
x + x + 60° = 180°
2x = 180° - 60° = 120°
x = 60°
Angle A = 60°
Since all the angles of the triangle OAB are equal, the triangle is an equilateral triangle.
Therefore, The Radius of the Circle (OA) = 5 cm [ This is because all the sides of an equilateral triangle are equal.]
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