in the figure,O is the centre of the circle and AB =CD. OM is perpendicular on AB line segment on CD . then prove that OM=ON.
As the above hypothesis has been prover logically, it becomes the theorem 'chords of equal length are at equal distance from the centre of the circle.'
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are u from telangana?????????
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Here
AB and CD are equal chord of a circle
and OM and ON perpendicular to AB and CD respectively.
since , equal chord are equidistant from the centre of the circle
so, OM =ON
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