in the figure 'O' is the centre of the circle and angle POR=120 find angle PQR and angle PSR
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Answered by
134
if there is figure like tis...remember that the central angle is the double of the upper angle..so if POR is 120. then PQR must be 60...
So PQR = 60°
PSR and PQR are supplementry
So PSR = 180 - PQR
PSR = 120°
Pls Mark As Břãįńĺíéšť.....
So PQR = 60°
PSR and PQR are supplementry
So PSR = 180 - PQR
PSR = 120°
Pls Mark As Břãįńĺíéšť.....
Answered by
59
angle PQR=anglePOR/2=120/2=60o
angle pqr+anglepsr=180o
anglePSR=180-anglePQR
=180-60=60o
angle PSR=120o
angle pqr+anglepsr=180o
anglePSR=180-anglePQR
=180-60=60o
angle PSR=120o
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