in the figure O is the centre of the circle . And <adb=120°,<oac=30°
find <acb
find<oab
justify that abc is an equileterql triangle
is the answer
<acb=60°
<oab=30°
<a=60°
<b=60°
<c=60°
<a=<b=<c
ab=bc=ca
the angles are in 60° and the sides of triangle are equal
therefore yhe triangle is an equileteral triangle
Answers
Answered by
7
Answer:
(1)∠ACB=
2
1
∠AOBbisectors
=
2
1
×(360
0
−140
0
)=
2
1
×220=110
0
(2)∠OBC=360
0
−(∠AOB+∠OAC+∠ACB)
=360
0
−(140
0
+50
o
+110
0
)
=360
0
−300
0
=60
0
(3)since,OA&OBisradius
∴ΔOABisisoscelesΔ
∴∠OAB=
2
1
(180
0
−140
0
)=
2
1
×40
0
=20
0
(4)∠CBA−∠OBC−∠OBA
=∠OBC−∠OAB[ΔOABisisoscelesΔ]
=60
0
−20
0
−40
0
Step-by-step explanation:
thx to my answers and mark it as brainlist
Similar questions